road problem

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1) 45= a(-50)^2+b(-500)+e

2) 30= a(500)^2+b(500)+e

3) -.09= 2a(-500)+b

4) .06= 2a(500)+b

Solve equations 3 and 4 for b by simply adding (a disappears)

The substitute back into one of 3 or 4 to find a

Then substitute a and b into one of equations 1 and 2 to find c

That system is basic algebra second semester kindergarten

 
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